Question 118252
If a soccer ball is kicked straight up from the ground with an initial velocity of 32 feet per second, then its height above the earth in feet is given by s(t)=-16t2 + 32t where t is time in seconds. Graph this parabola for 0-<t-<2. What is the maximum height reached by the ball?
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Maximum occurs when t = -b/2a = -32/(2*-16) = 1 second
The height when t = 1 second is s(1) = -16(1^2)+32(t) = 16 ft.
Plot the point (1,16)
The y-intercept occurs when t=0; s(0) = 0
Plot the point (0,0).
Draw a parabola through those two points an opening downward 
because of the negative on -16t^2
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Graph:
{{{graph(400,300,-5,5,-5,20,-16x^2+32x)}}}
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Cheers,
stan H.