Question 118221

{{{4x^2+8x=0}}} Start with the given equation


{{{4x(x+2)=0}}} Factor the left side.



Now set each factor equal to zero:

{{{4x=0}}} or  {{{x+2=0}}} 


{{{x=0}}} or  {{{x=-2}}}    Now solve for x in each case



So our answer is 

 {{{x=0}}} or  {{{x=-2}}} 



Notice if we graph {{{y=4x^2+8x}}} we can see that the roots are {{{x=0}}} and  {{{x=-2}}} . So this visually verifies our answer.



{{{ graph(500,500,-10,10,-10,10,0, 4x^2+8x) }}}