Question 117223
1.

{{{5x / (x - 1)  -  5 / (x - 1)}}}..........common denominator: {{{x-1}}}


={{{(5x-5) / (x - 1)  }}}........factor out common {{{5}}}


={{{5(x-1) / (x - 1)  }}}.........simplify


={{{5cross((x-1)) / cross((x - 1))  }}}


={{{5  }}}


2.


{{{2x^2 / (x-4)  - 32 /( x-4)}}}......common denominator: {{{x-4}}}


={{{(2x^2-32) / (x-4)}}}


={{{2(x^2-16) / (x-4)}}}.........factor out common {{{2}}}


={{{2(x^2-4^2) / (x-4)}}}......note the difference of the squares, factor it out


={{{2(x-4)(x+4)/ (x-4)}}}......simplify


={{{2cross((x-4))(x+4)/ cross((x-4))}}}......


={{{2(x+4)}}}


={{{2x+8}}}