Question 117327
{{{5x/(x-1) - 5/(x-1 )}}}…..common denominator is {{{x-1}}}


={{{(5x-5)/(x-1 )}}}…..factor out common {{{5}}} in nominator


={{{5(x-1)/(x-1 )}}}…..simplify


={{{5}}}...........your answer


2.


{{{2x^2/(x-4) - 32/(x-4)}}}………. common denominator is {{{x-4}}}


={{{(2x^2-32)/(x-4)}}}………. factor out common {{{2}}} in nominator


={{{2(x^2-16)/(x-4)}}}………. write {{{16}}} as a {{{4^2}}}


={{{2(x^2-4^2)/(x-4)}}}………. note the difference of squares and factor it out


={{{2(x-4)(x+4)/(x-4)}}}………. simplify


={{{(2(cross(x-4))(x+4))/(cross(x-4))}}}……….


={{{2(x + 4)}}}……….your answer