Question 118041
Celsius temperature readings can be converted to fahrenheit readings using the formula {{{F = (9/5)C+32}}}.  What is the fahrenheit temperature that corresponds to each of the following celsius temperatures:  -10,0,15,100?
<pre>
For the 1st one, replace the C in

{{{F = (9/5)C+32}}}

by {{{(-10)}}}

{{{F = (9/5)(-10)+32}}}

Write the {{{-10}}} as {{{(-10)/1}}}

{{{F = (9/5)((-10)/1) + 32}}} 

Multiply the numerators and denominators

{{{F = ((-90)/5) + 32}}}

Reduce the fraction {{{(-90)/5}}} to {{{-18}}}

{{{F = -18 + 32}}}

{{{F = 14}}}

-------------------------------

For the 2nd one, replace the C in

{{{F = (9/5)C+32}}}

by {{{(0)}}}

{{{F = (9/5)(0)+32}}}

Since anything time 0 is 0,

{{{F = 0+32}}}

{{{F = 32}}}

--------------------

For the 3rd one, replace the C in

{{{F = (9/5)C+32}}}

by {{{(15)}}}

{{{F = (9/5)(15)+32}}}

Write the {{{15}}} as {{{15/1}}}

{{{F = (9/5)(15/1) + 32}}} 

Multiply the numerators and denominators

{{{F = (135/5) + 32}}}

Reduce the fraction {{{135/5}}} to {{{27}}}

{{{F = 27 + 32}}}

{{{F = 59}}}

------------------------------

For the 4th one, replace the C in

{{{F = (9/5)C+32}}}

by {{{(100)}}}

{{{F = (9/5)(100)+32}}}

Write the {{{100}}} as {{{100/1}}}

{{{F = (9/5)(100/1) + 32}}} 

Multiply the numerators and denominators

{{{F = (900/5) + 32}}}

Reduce the fraction {{{900/5}}} to {{{180}}}

{{{F = 180 + 32}}}

{{{F = 212}}}

Edwin</pre>