Question 117985
I need to write an indirect proof for this problem:
Given- AB is not equal to DE & AC is congruent to CD
Prove measure of angle B is not equal to measure of angle E
there is a picture of two triangles facing each other and sharing one point- the tops of each triangle and the letters read from left to right- top left point A, middle point where both triangles meet point C, then next top point is point D, lower right point E, then C again, lower left point is point B. 
Sorry if that isn't enought info. but thanks for your help.
<pre><font face = "book antiqua" size = 5><b>
{{{drawing(200,200,-7,7,-6,6,line(5,4,-5.5,-4.4),line(-5,4,6,-4),
   line(-5.5,-4.4,-5,4),line(5,4,6,-4),locate(-5,5,A),
locate(5,5,D),locate(0,1.5,C),locate(-5.7,-4.5,B), locate(5.7,-4.3,E)  )}}}

1. Assume for contradiction that m<font face = "symbol">Ð</font>B = m<font face = "symbol">Ð</font>E

2. AC <font face = "symbol">@</font> CD    Given

3. m<font face = "symbol">Ð</font>ACB = m<font face = "symbol">Ð</font>DCE  (opposite or vertical angles)      

4. <font face = "symbol">D</font>ACB <font face = "symbol">@</font> <font face = "symbol">D</font>DCE   (ASA, angle-side-angle by 1,2,and 3)

5. AB = DE      (corresponding sides of congruent triangles)

6. AB <font face = "bookshelf symbol 7">m</font> DE      (given)

7.   5 and 6 contradict each other.

8. m<font face = "symbol">Ð</font>B = m<font face = "symbol">Ð</font>E (assumption in step 1 is false.)

Edwin</pre></font></b>