<PRE><B>Question 117967</B>
Divide:
2x^2 + 5x - 12
_______________    divided  2x^2 - 7x + 6
9x^2 - 16                   _____________
                            3x^2 - x -4

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Factor where you can:

[(2x^2+8x-3x-12)/(3x-4)(3x+4)] / [(2x^2-3x-4x+6)/(3x^2-4x+3x-4)]

=[(2x(x+4)-3(x+4))/(3x-4)(3x+4)] / [(x(2x-3)-2(2x-3))/(x(3x-4)+(3x-4)]

= [(x+4)(2x-3)/(3x-4)(3x+4)] / [(2x-3)(x-2)/(3x-4)(x+1)]

Cancel where you can:

Cancel (2x-3),(3x-4) leaving you with:

= [(x+4)/(3x+4)]/[(x-2)/(x+1)]

Invert the denominator and multiply:

= [(x+4)(x+1)]/[(3x+4)(x-2)]

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Cheers,
Stan H.</PRE>