Question 117969
Good afternoon Julie!  :)


An easier way to look at this problem is to write it in its exponential form.


{{{(144x^10y^12z^18)^(1/2)}}}


Taking the half-power of 144, we have 12,
From {{{x^10}}}, {{{x^5}}}
From {{{y^12}}}, {{{y^6}}}
And from {{{z^18}}}, {{{z^9}}}.


So our simplified expression is 


{{{12x^5y^6z^9}}}