Question 117950
two integers;

{{{x}}} and {{{x + 1}}}, whose squares differ by {{{25}}}

{{{x^2 + 25 = (x + 1)^2}}} 

{{{x^2 + 25 = x^2 + 2x + 1}}} 


{{{x^2 - x^2 =  2x + 1 - 25 }}} 

{{{0 =  2x - 24}}} 

{{{0 =  x - 12}}} 

{{{x=  12}}} 


and {{{x + 1= 13}}}


{{{12^2=144}}}

{{{13^2=169}}}

{{{169-144=25}}}