Question 117942
What's  ( (SQRT3) + i ) ^ 9
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Convert to trig form:
r = sqrt((sqrt3)^2+1^2) = 2
theta = tan^-1(1/sqrt3)= 30 degrees
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[2cis(30)]^9 = (2^9)cis(270)
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Convert back to complex form:

= 512(cos(270)+isin(270)
=512(0 + i (-1))
= -512i
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Cheers,
Stan H.