Question 117797
can somebody help me with this question? 

write the equation of the hyperbola in standard form having the given properties



center(0,0); vertices(+_3,0); foci(+_5,0)

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The vertices and foci are, respectively, a and c units from the center, and b^2=c^2-a^2

This hyperbola is in the form:
(x^2/a^2)-(y^2/b^2)=1


First, find the value of b^2--->b^2=c^2-a^2
=5^2-3^2
=25-9
=16

Now, you can write the standard equation for this hyperbola.
{(x^2/a^2)-(y^2/b^2)=1}

{(x^2/9)-(y^2/16)=1}

Hope that helps.

Greetings,
misscrt