Question 117940
A line passing through (-5,0) and (8,y) is perpendicular to a line with a slope 13/3. Find the value of y. My head rattles when I try to work this problem! Please help. Thanks!

If the line has slope 13/3, then the line passing thru it that is perpendicular has a value of slope that is the negative reciprocal of 13/3, which is -3/13.

Use the formula for slope to find the value of y:

m=y2-y1/x2-x1

-3/13 =(y-0)/(8-(-5))

-3/13=y/13

Cross multiply

(-3)(13)=(13)(y)

-39=13y

Solve for y

-39/13=13y/13

-3 = y

Hope that helps!

Greetings,
misscrt