Question 117912
Simplify:
{{{(x^2-3x-10)/(x^2-x-20)}}}
First, see if the trinomials in the numerator and the denominator are factorable.
Numerator:
{{{x^2-3x-10 = (x+2)(x-5)}}} 
Denominator:
{{{x^2-x-20 = (x+4)(x-5)}}}
So now you can rewrite the original problem using the factors of the trinomials:
{{{((x+2)*cross((x-5)))/((x+4)*cross((x-5)))}}} Cancel the factors as shown leaving you with:
{{{(x+2)/(x+4)}}}