Question 117818
{{{y=(650)/(2x+40))}}} Start with the given function




Looking at the numerator {{{650}}}, we can see that the degree is {{{0}}} since the highest exponent of the numerator is {{{0}}}. For the denominator {{{2x+40}}}, we can see that the degree is {{{1}}} since the highest exponent of the denominator is {{{1}}}.



<b> Horizontal Asymptote: </b>


Since the degree of the numerator (which is {{{0}}}) is less than the degree of the denominator (which is {{{1}}}), the horizontal asymptote is always {{{y=0}}}


So the horizontal asymptote is {{{y=0}}}




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<b> Vertical Asymptote: </b>

To find the vertical aysmptote, just set the denominator equal to zero and solve for x


{{{2x+40=0}}} Set the denominator equal to zero



{{{2x=0-40}}}Subtract 40 from both sides



{{{2x=-40}}} Combine like terms on the right side



{{{x=(-40)/(2)}}} Divide both sides by 2 to isolate x




{{{x=-20}}} Divide



So the vertical asymptote is {{{x=-20}}}





So looking at your answer, you are correct.