Question 117724
I think you mean {{{((2+5)/5)/((2(s+5))/15)}}}.


Just like when you learned to divide fractions, the rule is the same:  Invert the divisor and multiply:


{{{((2+5)/5)/((2(s+5))/15)}}}


{{{((2+5)/5)*(15/(2(s+5)))}}}


Before you actually multiply the numerators and the denominators, eliminate some common factors.


{{{((2+5)/1)*(3/(2(s+5)))}}}
{{{(7/1)*3/(2s+10)}}}
{{{21/(2s+10)}}}


Looking at this, I think you may have made a typing error, just based on the fact that there is a trivial addition in the numerator of the dividend fraction.  So, if it really looks like this:


{{{((s+5)/5)/((2(s+5))/15)}}}, then it works out a little differently:


{{{((s+5)/5)*(15/(2(s+5)))}}}


{{{((s+5)/1)*(3/(2(s+5)))}}}


{{{(1/1)*(3/2)}}}


{{{3/2}}}