Question 117740
let the length of a rectangle be {{{a =(7/8)yd}}} and its width be {{{b=(32/49) yd}}}
then area {{{A}}} will be: 


{{{A = a*b}}}....substitute {{{a}}} and {{{b}}}

{{{A = (7/8)yd*(32/49)yd}}}

{{{A = (7/8)(32/49)yd^2}}}…………….

{{{A = ((7*32)/(8*49))yd^2}}}…………….simplify..(divide {{{7}}} and {{{49}}} by {{{7}}}, as {{{8}}} and {{{32}}} by {{{8}}} as well)

{{{A = ((1*4)/(1*7))yd^2}}}

{{{A = (4/7)yd^2}}}