Question 117705
 y(x)=x^2-6x+7
=x^2-6x+9-9+7  complete the square.
=(x-3)^2-2
y=a(x-h)^2+k
a=1, h=3, k=-2
Vertex=(h,k)=(3,-2)=(Xv,Yv)
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the y intercept=y(0)=7
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the x intercepts=
x^2-6x+7=0
(x-3)^2-2=0 See above.
(x-3)^2=2
x-3=+-sqrt(2) Take sqrt of both sides.
x=3+-sqrt(2) the x intercepts.
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Ed
{{{graph(500,500,-10,10,-10,10,x^2-6x+7)}}}