Question 117653


Given:

The length {{{L}}} is {{{5ft }}} less than twice its width{{{W}}}  :

{{{L + 5ft = 2W}}}………=>…. {{{ (L + 5ft)/2 = W}}}………

the perimeter {{{P = 230ft }}}

{{{P = 2(L+W)}}}

{{{230ft = 2(L+(L + 5ft)/2)}}}

{{{230ft = 2(L+L/2 + 5ft/2)}}}


{{{230ft = 2L+ 2L/2 + 2*5ft/2}}}

{{{230ft = 2L+ L + 5ft}}}

{{{230ft = 3L + 5ft}}}

{{{230ft – 5ft = 3L }}}

{{{225ft  = 3L }}}

{{{225ft /3 = 3L/3 }}}

{{{75ft = L }}}

{{{ (L + 5ft)/2 = W}}}………

{{{ (75ft + 5ft)/2 = W}}}

{{{ 80ft /2 = W}}}

{{{ 40ft  = W}}}


Check:

{{{P = 2(L+W)}}}
{{{230ft = 2( 75ft + 40ft)}}}

{{{230ft = 2*115ft}}}

{{{230ft = 230ft}}}