Question 117635
The sum of two numbers is 25 and the sum of their squares is 313.  Find the numbers.  (Express one number as x, the other in terms of x).
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Let one of the numbers be "x" ; the other number is "25-x".
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EQUATION:
x^2 + (25-x)^2 = 313

x^2 + 625 - 50x + x^2 = 313

2x^2 -50x + 212 = 0

x^2-25x+106 = 0

x = [25 +- sqrt(625-4*106)]/2

x = [25 +- sqrt(201)]/2

x = (25+sqrt(201))/2 = 19.5887
OR
x = (25-sqrt(201)/2 = 5.4113

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Cheers,
Stan H.