Question 17657
2t^3 -6t + 1 = 0
*[invoke solve_quadratic_equation 2, -6, 1]

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But if you're question is:
2t^3 -6t + 1 = 0
Then,
t(2t^2-6)=-1
then t=-1 or (2t^2-6)=-1
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(2t^2-6)=-1
2t^2=-1+6
t^2=5/2
{{{ t=sqrt(5/2) }}}
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Then {{{ t=-1}}} or {{{ t=sqrt(5/2) }}}
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Hope this helps,
Prabhat