Question 117389

{{{3x^2-23x+97-(396/x+4)}}}……….multiply both terms by {{{x+4}}}
	
{{{(x+4)(3x^2-23x+97)-(396/x+4)(x+4)}}}……….

{{{(x+4)(3x^2-23x+97) -396}}}……….

{{{3x^3-23x^2+97x +12x^2-92x+388 -396}}}……….

{{{3x^3-11x^2 + 5x  -8}}}……….move {{{-8}}} to the right

{{{x(3x^2-11x+ 5)  -8}}}……….the quadratic {{{3x^2-11x+ 5}}}cannot be factored, so your answer is:
	
{{{x(3x^2-11x+ 5)  -8}}}