Question 17659
Let the remaining term be y
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x^2 + 2/3x + y
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{{{ (a+b)^2=a^2+b^2+2ab }}}
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{{{ x^2+2(1/3)(x)+ y^2 }}}
So y=1/3
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So we get
{{{ (x+(1/3))^2 = x^2+2(1/3)(x)+ y^2 }}}
{{{ (x+(1/3))^2 = x^2+2(1/3)(x)+ (1/9) }}}
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Then we have
<font color=blue>x^2 + 2/3x + 1/9</font>
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Hope this helps,
Prabhat