Question 117544



{{{-2(3x+2)(8x+1)(9x-5)=0}}} Start with the given equation




Now set each factor equal to zero:


{{{3x+2=0}}}, {{{8x+1=0}}} or {{{9x-5=0}}}


Now solve for x for each factor:


{{{x=-2/3}}}, {{{x=-1/8}}} or {{{x=5/9}}}


So the zeros of {{{-2(3x+2)(8x+1)(9x-5)}}} are {{{x=-2/3}}}, {{{x=-1/8}}} or {{{x=5/9}}}