Question 117496
let the integers be x & (x+1).
(1/x)+[1/(x+1)]=7/12 find a common denominator and combine these fractions on the left. x(x+1) 
(x+1+x)/x(x+1)=7/12
(2x+1)/(x^2+x)=7/12 now cross multiply
7(x^2+x)=12(2x+1)
7x^2+7x=24x+12
7x^2+7x-24x-12=0
7x^2-17x-12=0
(7x+4)(x-3)=0
x-3=0
x=3 answer
so the integers are 3 & 4
proof
1/3+1/4=7/12
(4+3)/12=7/12
7/12=7/12