Question 17687
{{{ (3+2*sin(theta))/(1-2*sin(theta)) }}}

Now sin(theta) is 1 for 90 degrees
So if theta is 90 we get

{{{ (3+2*sin(90))/(1-2*sin(90)) }}}
{{{ (3+2)/(1-2) }}}
{{{ 5/-1 }}}
{{{ -5 }}}

Hence it is an imaginary (non-real) value.

<P>
Again,for theta=0,sin becomes 0

{{{ (3+2*sin(0))/(1-2*sin(0)) }}}
{{{ (3+0)/(1-0) }}}
{{{ 3/1 }}}
{{{ 3 }}}
Which is real.
<P>
Hence for given expression we get,
Real values,theta=0 degreees
Imaginary values,theta=90 degrees
<P>
Hope this helps,
Prabhat