Question 117535
How do you solve 2n^2-4n=6 and then put it into a table or graph?
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2n^2-4n-6 = 0
2(n^2-2n-3) = 0
(n-3)(n+1) = 0
n = 3 or n = -1
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y= 2n^2-4n-6
It has x-intercepts at (3,0) and at (-1,0)
The vertex is at x=-b/2a = 4/(4) = 1 ; f(1) = 2-4-6 = -8
So the vertex is at (1,-8)
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With those three points you can graph the parabola.
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Graph:
{{{graph(400,300,-10,10,-10,10,2x^2-4x-6)}}}
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Cheers,
Stan H.