Question 117326
Perform the indicated operation.

n squared +5n+4 / 2n squared+2n TIMES n squared -n-12 / n squared-16
{{{((n^2+5n+4))/((2n^2+2n))}}} * {{{((n^2-n-12))/((n^2-16))}}}
:
Factor:
{{{((n+4)(n+1))/(2n(n+1))}}} * {{{((n-4)(n+3))/((n-4)(n+4))}}}
:
You can cancel (n+4),(n+1) and (n-4)
{{{1/(2n)}}} * {{{(n+3)}}} = {{{((n+3))/(2n)}}}
:
:
3pq cubed / 5 DIVIDED BY 9p squared q squared / 10
{{{3pq^3/5}}}
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{{{9p^2q^2/10}}}
:
Remember when you divide fractions, you invert the dividing fraction & Multiply
{{{3pq^3/5}}} * {{{10/(9p^2q^2)}}}
:
Cancel 3 into 9, 5 into 10, p into p^2 and q^2 into q^3, results
{{{q * (2/3p)}}} = {{{(2q)/(3p)}}}
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Did this make sense to you, any questions?