Question 116642
{{{1/(x+2)  +  8/(x-2)}}}


You work this just like any other addition of fractions problem.  First find the common denominator:  {{{(x+2)(x-2)=x^2-4}}}, so


{{{(x-2)/(x^2-4)  +  8(x+2)/(x^2-4)}}}
{{{((x-2) +  8(x+2))/(x^2-4)}}}
{{{(x-2+8x+16)/(x^2-4)}}}
{{{(9x+14)/(x^2-4)}}}