Question 117495
Let x = the denominator
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"the numerator of a certain fraction is 2 more than the denomenator.
{{{((x+2))/x}}}
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"if 1/3 is added to the fraction, the result is 2"
{{{((x+2))/x}}} + {{{1/3}}} = 2 
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find the fraction
Multiply equation by 3x to eliminate the denominators
3x*{{{((x+2))/x}}} + 3x*{{{1/3}}} = 3x(2)
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Cancel out the denominators and you have:
3(x+2) + 1x = 6x
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3x + 6 + x = 6x
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4x + 6 = 6x
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6 = 6x - 4x
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6 = 2x
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x = {{{6/2}}}
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x = 3
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Check our solution in original equation
{{{((3+2))/3}}} + {{{1/3}}} = 2
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{{{(5)/3}}} + {{{1/3}}} = 2; confirms our solution
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Did I make this understandable, any questions?