Question 998682
<pre>
solve for x

x= 6/8 (log(base6) sqrt(108) - 1 log(base6) (2/sqrt(3))+ 2 log (base6) 9 + log(base6) 64)

I am not sure how to find X, I would appreciate if someone can help me. I will provide my step.

x=6/8 (log(base6) sqrt(108) - 1 log(base6) (2/sqrt(3))+ 2 log (base6) 9 + log(base6) 64)

 =6/8 (log(base6) sqrt(108)/ (2/sqrt3) + log(base 6) 9^2 + log(base6) 64)

 =6/8 (log(base6) sqrt(108) / (2/sqrt3) + log(base 6) (81)(64)

 =6/8 (log(base6) 9 + log(base6) 5184)
 
 =6/8 (log(base6) (9)(5184)

 =6/8 (log(base6) 46656)

 = log(base6) 34992
*******************<font color = blue><font size = 2><font face = tahoma><b>
{{{x = (6/8)(log (6, (sqrt(108))) - log (6, (2/sqrt (3))) + 2*log (6, (9)) + log (6, (64)))}}}
{{{x = (6/8)(log (6, (sqrt(108))) - log (6, (2/sqrt (3))) + log (6, (9)^2) + log (6, (64)))}}}
{{{x = (6/8)(log (6, (sqrt(108))) - log (6, (2/sqrt (3))) + log (6, (81)) + log (6, (64)))}}}
{{{x = (6/8)(log (6, ((sqrt(108)/(2/sqrt(3)))(81)(64))))}}}
{{{x = (6/8)(log (6, (sqrt(108)(sqrt(3)/2))(81)(64)))}}}
{{{x = (6/8)(log (6, (sqrt(108)(sqrt(3)/cross(2)))(81)32cross((64))))}}}
{{{x = (6/8)(log (6, (sqrt(108)sqrt(3)(81)(32))))}}}
{{{x = (6/8)(log (6, (sqrt(108*3)(81)(32))))}}}
{{{x = (6/8)(log (6, (sqrt(324)(81)(32))))}}}
{{{x = (6/8)(log (6, (18*81*32)))}}}
{{{x = (6/8)(log (6, ((9*2)(9^2)(16*2))))}}}
{{{x = (6/8)(log (6, ((3^2*2)(9^2)(4^2*2))))}}}
{{{x = (6/8)(log (6, (3^2 * 9^2 * 4^2 *2^2) ))}}}
{{{x = (6/8)(log (6, (3 * 9 * 4 * 2)^2))}}}
{{{x = (6/8)(log (6, (216)^2)))}}}
{{{x = (6/8)(log (6, (6^3)^2))}}}
{{{x = (6/8)(log (6, (6^6)))}}}
{{{x = log (6, (6^6)^(6/8))}}}
{{{matrix(2,1, " ", x = log (6, (6^(36/8))))}}}
{{{matrix(2,1, " ", x = log (6, (6^(9cross(36)/2cross(8)))))}}}
{{{matrix(2,1, " ", x = log (6, (6^(9/2))))}}}
{{{highlight(x) = highlight(9/2)}}} ---- Applying {{{log (b, (b^c)) = c}}}
</font></font></font></b></pre>