Question 728593
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Please help

Solve: (sqrt of 2x - 3) = x - 1

Solve: (sqrt of 3x - 3) - (sqrt of x) = 1
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Again, respondent @MathLover1(20855) used the QUADRATIC EQUATION formula to solve both quadratic equations,
which is UNNECESSARY, since the resultant TRINOMIALS are FACTORABLE! 

Furthermore, for {{{sqrt(3x - 3) - sqrt(x) = 1}}}, she got 2 values for x: x = 4, and x = 1. Obviously, when checked, the value 1 DOES
NOT SATISFY this equation, thereby making 1, an EXTRANEOUS solution. So, in this case, x = 4 is the SOLE VALID and
ACCEPTABLE SOLUTION.</font></font></font></b></pre>