Question 184851
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A bus averages 6 kilometers an hour less than a passenger car. 
The bus travels 80 kilometers in the same time that the car travels 112 kilometers. Find the rate of each.
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        Calculations in the post by @HyperBrain are irrelevant to the given problem, since 

        in his calculations, @HyperBrain uses different numbers from the given in the post.

        It leads him to wrong answer.


        I came to bring a correct/adequate solution.



<pre>
Step 1:

Let x be the rate of the passenger car
    Then x-6 is the rate of the bus

Note: distance=rate*time so time=distance/rate


Step 2: Write the algebraic equation

80/(x-6) = 112/x


Step 3: multiply both sides by x(x-6)

80x = 112(x-6)
80x = 112x-672
32x = 672
x = 672/32 = 21   Therefore, the passenger car travels at the rate of 21 km/hr.
x-6 = 21-6 = 15   Therefore, the bus travels 15 km in 1 hr.


<U>CHECK for the travel time</U>: {{{80/15}}} = 5{{{1/3}}}  hours.

                           {{{112/21}}} = 5{{{1/3}}} hours, the same time.

                           Precisely correct !
</pre>

Solved correctly.



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The fact that @HyperBrain repeats these words "Power up, @HyperBrain!" from post to post,
tells me that he uses a computer code.


The fact that @HyperBrain makes numerous errors of the same type from post to post, 
tells me that his computer code is erroneous and incorrectly reads the input data.