Question 211804
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Trigonometry-basics/211804: if a=22, b=14, and c=30, find the area of triangle ABC.
a)33 sq units
b)121.0 sq units
c)130.2 sq units
d)143.8 sq units
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        Calculations in the post by @HyperBrain are Hyper-incorrect.

        I came to bring a correct solution.



To find the area, apply the Heron's formula


        A = {{{sqrt(s(s-a)(s-b)(s-c))}}}


where {{{s=(a+b+c)/2}}}


Here, s = {{{(22+14+30)/2}}} = 33.


So,

{{{A=sqrt(33(33-22)(33-14)(33-30))}}}
{{{A=sqrt(33*11*19*3)}}}


A = 143.8 square units (rounded).    &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<U>ANSWER</U>


Solved correctly.