Question 211794
.
in triangle ABC, A=47 degrees, b=12, c=8. find a to the nearest tenth
a)6.3
b)8.7
c)8.8
d)18.4
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The standard method of solution is to apply the cosine low


    a = {{{sqrt(b^2 + c^2 - 2bc*cos(A))}}} = {{{sqrt(12^2 + 8^2 - 2*12*8*0.682)}}} = 8.778 square units.


<U>ANSWER</U>.  8.8 square units (rounded as requested).