Question 945054
If the second number is 5 less than the first number, then these ARE NOT consecutive  "integers".   How "consecutive" is meant, not clear.


x, the first;
x-5, the second?;
x+15, the third


{{{x+(x-5)+x+15=56}}}

{{{3x+10=56}}}

{{{3x=46}}}

{{{x=46/3}}}

{{{x=15&1/3}}}


The numbers would be
{{{system(15&1/3, 10&1/3, 30&1/3)}}}
and are Rational Numbers.


If these numbers are to be consecutive,  then from smallest to largest they are {{{system(10&1/3,15&1/3,30&1/3)}}}.