Question 949907
.
Find all values of t in the interval [0, 2π] satisfying the given equation. 
(Enter your answers as a comma-separated list.)
(4 cot t)^2 = 48
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~



        The solution in the post by @lwsshar3 is INCORRECT.

        Below is my correct solution.



<pre>
(4*cos(t))^2 = 48

16cot(t)^2 = 48

cot(t)^2 = 48/16 = 3

cot(t) = +/- {{{sqrt(3)}}}

t = {{{pi/6}}}, {{{5pi/6}}},  {{{7pi/6}}},  {{{11pi/6}}}.    <U>ANSWER</U>
</pre>

Solved correctly.