Question 117435
{{{-(20b^ 2/3a )* (15a ^3 /5b)}}}...multiply nominator by nominator and denominator by denominator
	
{{{-(20b^ 2*15a ^3) /(3a*5b)}}}....cancel {{{15}}} from nominator, {{{5}}}, and {{{3}}} from denominator

{{{-20b^ 2*a ^3 /(a*b)}}}....cancel {{{a}}} and {{{b}}}from denominator

{{{-20a ^2*b }}}