Question 968610
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The wording of the post is certainly strange; but the intention is clear: find the vertex.<br>
{{{f(x)=-x^2-10x-30}}}<br>
Given a quadratic function {{{f(x)=ax^2+bx+c}}}, the x-coordinate of the vertex is {{{-b/(2a)}}}:<br>
{{{-(-10)/(2(-1))=10/-2=-5}}}<br>
The y-coordinate of the vertex is found by evaluating the function at that value of x:<br>
{{{f(-5)=-(-5)^2-10(-5)-30=-25+50-30=-5}}}<br>
ANSWER: The vertex is (-5,-5)<br>
The graph....<br>
{{{graph(400,400,-10,5,-25,5,-x^2-10x-30)}}}<br>