Question 970565
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Find all solutions on the interval (0,2pi)
12tan^2(x)=4
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        In the post by @lwsshak3, the values of angles in the answer are determined INCORRECTLY.

        I came to bring a correct solution.



12tan^2(x)=4
12tan^2(x) = 4
tan^2(x) = {{{4/12}}} = {{{1/3}}}
tan(x) = +/- {{{sqrt(3)/3}}}
x = &nbsp;{{{pi/6}}}, &nbsp;{{{5pi/6}}}, &nbsp;{{{7pi/6}}}, &nbsp;{{{11pi/6}}}.  &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<U>ANSWER</U>



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After checking many solutions by @lwsshak3, I see that his level in Trigonometry
is lower than in other topics. He makes errors in this area which a professional tutor 
should not make.