<PRE><B>Question 148962</B>
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{{{2x^2-5x-3=0}}}
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Good choice is Quadratic Formula solution or you could try to factor.


Directly into general formula solution  {{{x=(5+- sqrt(5^2-4*2*(-3)))/(2*2)}}}

{{{(5+- sqrt(25+24))/4}}}

{{{(5+- sqrt(49))/4}}}

{{{(5+- 7)/4}}}

3  or  -1/2



The quadratic trinomial IS factorable but you can do that on your own.


If you wanted to solve by Completing the Square, you can but more effort.

{{{x^2-(5/2)x-3/2=0}}}

and the term to complete the square is {{{(5/(2*2))^2}}} which you would add to both sides.</PRE>