Question 1210598
To find the probability of obtaining a reading less than -0.903°C in a normal distribution with a mean of 0°C and a standard deviation of 1.00°C, we can use the Z-score formula:

Z = (X - μ) / σ

Z = (-0.903 - 0) / 1 = -0.903

Using a Z-table or calculator, the probability for Z = -0.903 is approximately 0.1029. Thus, the probability of obtaining a reading less than -0.903°C is about 10.29%.