Question 473939
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How do i solve this log5^7+1/2log5^4=log5^x
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The other person got x = 9, but this author disagrees, as this most likely is: 
  {{{log (5, (7)) + (1/2)log (5, (4)) = log (5, (x))}}}
{{{matrix(2,1, " ", log (5, (7)) + log (5, (4^(1/2)))) = log (5, x))}}} --- Applying {{{a*log (b, c))}}} = {{{log (b, (c^a))}}}
         {{{log (5, (7)) + log (5, (2)) = log (5, (x))}}}
                     {{{log (5, (7*2)) = log (5, (x))}}} ---- Applying {{{log (b, (a)) + log (b, (c))}}} = {{{log (b, (a*c))}}}
                      {{{log (5, (14)) =  log (5, (x))}}}
                                 14 = x --- LOG bases are same, so LOG arguments are EQUIVALENT

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