Question 117405
Let the integers be (n-1), n, (n+1).
4 times middle integer = 4n
4 times middle integer plus the larges integer = 4n + (n-1) = 5n-1
6 times the smallest integer = 6(n-1)


According to the given conditions
5n-1 = 6(n-1) - 9
5n - 1 = 6n - 6 - 9
5n - 1 = 6n - 15
6n - 5n = 15 + 1
n = 16


Hence, the nos. are (16 - 1 =) 15, 16 and (16 + 1 =) 17.