Question 1210602
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        The solution is more than obvious.


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The figure is the union of this basic shapes


    - a rectangle 6 x (3+2+2) = 6 x 7 square meters;

    - a semicircle of the diameter (6+(6-2)) = 10 meters (the radius is 10/2 = 5 meters);

    - an isosceles right-angled triangle with the leg size of 3 m;

    - a square of the side length 2 m.



Accordingly, the total area is this sum

      6^7 + {{{(1/2)*pi*5^2}}} + {{{(1/2)*3*3}}} + {{{2*2}}} = 

    = 42 + (1/2)*3.14159*25 + (1/2)*9 + 4 = 89.769875 m^2.


You may round it reasonably and get the


<U>ANSWER</U>.  The total area is  89.77 m^2 rounded with two decimal after the decimal point.
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Solved.