Question 626102
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The question is......Two jets leave at the same time,one is flying eat, the other west. the speed of the jet that is flying
west is 75km/h faster than the speed of the jet flying east. in 3 hr they are 3075km apart. let w represent the speed of the
plane travelling west and e represent the speed of plane travelling east. you need to know the speed of each plane. write a
system of equation to model this situation
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The other "PERSON" totally ignored the given instructions, regarding the assigned variables. It/He/She even came up with a solution,
although one wasn't requested. 

As requested, speeds of westbound and eastbound jets are w, and e, respectively
Since the westbound jet is travelling 75 km/h faster than the eastbound, we get the following SPEED equation: w = e + 75 ---- eq (i)

Also, it takes the jets 3 hrs to be 3,075 km apart, at which time, the westbound had travelled "3w" km, and the eastbound, "3e" km,
resulting in the following DISTANCE equation: 3w + 3e = 3,075
                                                                               3(w + e) = 3(1,025)
                                                                                    w + e = 1,025 --- eq (ii)
                                                                                           w = e + 75 -- eq (i)

The above 2-system equation can be easily solved using SUBSTITUTION.
It can also be solved using ELIMINATION, but written as follows: w - e = 75 ----- eq (i)
                                                                                                               w + e = 1,025 -- eq (ii)
         
That's IT!. That's ALL that's needed.</font></font></font></b></pre>