Question 287802
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3/(x+1) +4/(x-2)=(px+q)/(x+1)(x-2)
What is the value of p and q?
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        The answer in the post by @mananth is incorrect.

        I came to bring a correct solution.



3/(x+1) +4/(x-2)=(px+q)/(x+1)(x-2)


Multiply both sides by (x+1)*(x-2).
You will get an equivalent equality


3(x-2)+4(x+1)= (px+q)(x+1)(x-2)/(x+1)(x-2)

3x-6+4x+4 = (px+q)

7x-2 = px+q


Hence,  p = 7, q = -2.


<U>ANSWER</U>.  &nbsp;&nbsp;p = 7,  &nbsp;&nbsp;q = -2.



At this point, the solution is complete.