Question 416707
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Please help me solve this equation! log2 x+ log2 (x+1)=1
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        Below is my complete correct solution 



log2(x) + log2(x+1) = 1


The domain for this equation is the set of all real positive numbers x > 0.


In this domain, the given equation is equivalent to this one 


log2(x*(x+1)) = 1


Simplify and find x


x(x+1) = 2^1, 
x^2+x-2 = 0
(x+2)(x-1) = 0
x = -2, 1


x = -2  is an extraneous solution out the domain, so we disregard x = -2
(since logarithm of the negative argument is not defined).


Thus, x = 1 is the unique real solution to the original equation. &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<<<---===  &nbsp;&nbsp;<U>ANSWER</U>


Solved.