Question 416707
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Please help me solve this equation!    log2 x+ log2 (x+1)=1 
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{{{log (2, (x)) + log (2, (x + 1)) = 1}}}, with x > 0

The other person's claim, that - 2 is a solution to this equation, is FALSE.
1 is, though, since it's > 0!!</font></font></font></b></pre>