Question 686407
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Please help me solve this equation:

Solve:  log2 (x+5) + log2 (x+1) = 5
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The following response from the other person doesn't do much to answer this problem, or help
the "POSTER: "log(x+1)/log 2 +log*x+5)/log(2)=5"

{{{log (2, (x + 5)) + log (2, (x + 1)) = 5}}}, with x > - 1
       {{{log (2, ((x + 5)(x + 1))) = 5}}} ------ Applying {{{log (b, (c)) + log (b, (d))}}} = {{{log (b, (c*d))}}}
          {{{log (2, (x^2 + 6x + 5)) = 5}}}
                      {{{x^2 + 6x + 5 = 2^5}}} ---- Converting to EXPONENTIAL form
                      {{{x^2 + 6x + 5 = 32}}}
                    {{{x^2 + 6x - 27 = 0}}}
                (x - 3)(x + 9) = 0
                               x - 3 = 0     or      x + 9 = 0 ---- Setting each FACTOR equal to 0
                                     x = 3    or              x = - 9 (IGNORE)

The above x-value, - 9, is IGNORED because x MUST be > - 1, and x = - 9 is CLEARLY NOT!

So, only VALID/ACCEPTABLE solution is: <font color = red><font size = 3>x = 3</font></font></b></pre>