Question 282707
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The area of a square is 12 more than its perimeter. Find the length of a side.
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        The solution in the post by @mananth is incorrect, since his setup equation is incorrect.

        I came to bring a correct solution.



<pre>
Let x be the side length of the square.


The setup equation is

    x^2 = 4x + 12,

according to the problem.


Reduce it to the standard form of a quadratic equation and factorize

    x^2 - 4x - 12 = 0,

    (x-6)*(x+2) = 0.


The roots are x= 6  and  x= -2.


Since we look for a side length, we choose the positive root and reject the negative one.


<U>ANSWER</U>.  The side of the square is 6 units.
</pre>

Solved correctly.


You may check mentally that the answer value satisfies the problem's condition.